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Although this equation looks very complicated, it should not present
any great difficulties:
\[ \int\frac{\sqrt{(ax+b)^3}}{x}\,dx = \frac{2\sqrt{(ax+b)^3}}{3}
  + 2b\sqrt{ax+b} + b^2\int\frac{dx}{x\sqrt{ax+b}} \]
The same applies to $\int^8_{-1}(dx/\sqrt[3]{x}) = \frac{3}{2}(8^{2/3} +
  1^{2/3}) = 15/2$
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